The concept is easy enough to carry over to dice, but from that rouletteforum post, the biggest problem translating into dice is the multiple games to a single bet (b2 from forum post): Betting on red (which has a 47.4% chance to win) and even at the same time (also 47.4% chance to win).
Lose both: (bet 20, lose 20, win 0) -20 profit
Win one but lose the other: (bet 20, lose 10, win 10) 0 profit
Win both: (bet 20, win 20, lose 0) 20 profit
This can't be done in dice unless you make 2 distinct bets. With b1, you can reduce the 4 wagers into a single bet. your odds of hitting any one of the 4 numbers are 4/37=10.81% so play at that chance. alternatively you can chase the same payout which will have a better chance for dice games (you can only win 1 of the 4, so if you bet 4 total, one wins and returns 35x, thus you make 31 profit and a payout of 8x ~ 12.375% chance to win)
If we assume that you split b2 into 2 bets and keep b1 as a single bet, the process can be broken up into:
is it the first or second bet of a sequence?
-bet 10 low at 49.5%
-increment bet sequence number
was the previous bet the first part of b2
-bet 10 on 49.5% high
-increment bet sequence number
is it the third or 4th bet of a sequence and is your balance%3==0)
-mark that it's the first bet of b2
-bet 10 on 49.5% low
else
-mark that it's not the first bet of b2
is it the 3rdor 4th bet of a sequence and is your balance%3!=0)
-bet 8 at 12.357% chance to win
-increment bet sequence number
reset bet sequence if over 4
Now put that into code and let us know how it goes
